Question

# If the sum of odd numbered terms and the sum of even numbered terms in the expansion of (x+a)n are A and B respectively, then the value of (x2−a2)n is

A

A2B2

B

A2+B2

C

4AB

D

None of these

Solution

## The correct option is A A2−B2 A2−B2 If A and B denote respectively the sum of odd terms and even terms in the expansion (x+a)n Then, (x+a)n=A+B....(1) (x−a)n=A−B....(2) Multiplying both the equations we get (x+a)n(x−a)n=A2−B2 ⇒(x2−a2)n=A2−B2 MathematicsRD SharmaStandard XI

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