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Question

If the sum of odd numbered terms and the sum of even numbered terms in the expansion of (x+a)n are A and B respectively, then the value of (x2a2)n is



A

A2B2

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B

A2+B2

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C

4AB

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D

None of these

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Solution

The correct option is A

A2B2


A2B2

If A and B denote respectively the sum of odd terms and even terms in the expansion (x+a)n

Then, (x+a)n=A+B....(1)

(xa)n=AB....(2)

Multiplying both the equations we get

(x+a)n(xa)n=A2B2

(x2a2)n=A2B2


Mathematics
RD Sharma
Standard XI

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