If the sum of the digits of any number between 100 and 1000 be subtracted from that number, by what number is the result divisible?
A
0
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B
2
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C
3
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D
4
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Solution
The correct option is C3 A three digit number is represented by 100x+10y+z
where, x is the digit at the hundreds' place, y at tens' place and z at ones' place. Now, 100x+10y+z−(x+y+z)=99x+9y=9(11x+y) ∴ The result is always divisible by 3,9.