If the sum of the distances of a variable point from two perpendicular lines in a plane is 1, then its locus is
A
A square
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B
A circle
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C
A straight line
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D
Two intersecting lines
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Solution
The correct option is A A square Let P is a variable point whose coordinates are (h,k) and x-axis and y-axis are two perpendicular lines. So PM+PN=1 ⇒|k|+|h|=1 ⇒|x|+|y|=1 which is required focus and is square