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Question

If the sum of the first n terms of an AP is 4nn2, what is the first term (that is S1) What is the sum of first two terms? What is the second term? Similarly, find the 3rd, the 10th and the nth terms.

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Solution

sn=4nn2
Tn=snsn1
Tn=4nn24(n1)+(n1)2
Tn=4nn24n+4+n22n+1
Tn=2n+5
T1=2×1+5=3
T2=2×2+5=1
T3=2×3+5=1
T10=2×10+5=15
sum of first two terms=T1+T2=3+1=4
second term=T2=1
third term=T3=1
tenth term=t10=15

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