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Question

If the sum of three numbers in A.P. is 24 and their product is 440, find the numbers.


Solution

Let 3 numbers in A.P. be
a - d, a and a + d
(ad)+(a)+(a+d)=243a=24a=8
and product =
(ad)(a)(a+d)=440(a2d2)a=440(82d2)×8=44082d2=55d2=9d=±3
With a = 8, d = 3, we have 5, 8, 11
With a = 8, d = -3, we have 11, 8, 5


Mathematics
RD Sharma
Standard XI

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