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Question

If the two circles (x1)2+(y3)2=r2 and x2+y28x+2y+8=0 intersect in two distinct points, then

A
r < 2
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B
r = 2
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C
r > 2
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D
2 < r < 8
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Solution

The correct option is D 2 < r < 8
Circle intersect at two district points -
c1c2<r1+r2
32+42<r+3
5<r+3
r>2
Also, r1r2<c1c2
r3<5
r<8
2<r<8
Hence, the answer is 2<r<8.


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