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Question

If the two determinants D1 and D2 given below be equal, then prove that
cos2θ+cos2ϕ+cos2ψ=1 where
D1=∣ ∣1cosθcosϕcosθ1cosψcosϕcosψ1∣ ∣
D2= ∣ ∣0cosθcosϕcosθ0cosψcosϕcosψ0∣ ∣

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