Let I=∫dxcos(3x−2)⋅cos(3x+5)
I=∫dxcos(3x−2)⋅cos(3x+5)×sin7sin7
⇒I=1sin7[sin((3x+5)−(3x−2))cos(3x−2)⋅cos(3x+5)dx
⇒I=(1sin7)∫sin(3x+5)(cos(3x−2)−cos(3x+5)sin(3x−2)cos(3x−2)cos(3x+5)dx
⇒I=1sin7∫tan(3x+5)−tan(3x−2)dx
⇒I=ln|sec(3x+5)|−ln|sec(3x−2)|3sin7+C
∴I=ln∣∣∣sec(3x+5)sec(3x−2)∣∣∣3sin7