CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If the vectors $$\displaystyle \vec{P}= a\tilde{i}+a\hat{j}+3\hat{k}\:and\:\vec{Q}= a\hat{i}-2\hat{j}-\hat{k}$$ are perpendicular to each other then the positive value of a is


A
zero
loader
B
1
loader
C
2
loader
D
3
loader

Solution

The correct option is B 3
Given, perpendicular, implies $$\vec{P}.\vec{Q}=0$$
or, $$(a\hat{i}+a\hat{j}+3\hat{k}).(a\hat{i}-2\hat{j}-\hat{k})=0$$
or, $${a}^{2}-2a-3=0$$
Solving the quadratic, we get, $$a=3$$ or $$-1$$. 
Positive value is thus $$3$$.

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image