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Question

If the velocity of a particle is v=At+Bt2, where A and B are constants, then the distance travelled by it between 1 s and 2 s is

A
32A+4B
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B
3A+7B
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C
32A+73B
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D
A2+B3
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Solution

The correct option is B 32A+73B
We know that v=dSdt

Integrating, S=t=2t=1vdt=21(At+Bt2)dt=A/2(221)+B/3(231)=32A+73B

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