If the vertex of the parabola $y = 3 x^{2} - 12 x + 9$ is $(a, b)$ , then the parabola whose vertex is $(b, a)$ , is (are).

y = x^{2} + 6 x + 11

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y = x^{2} - 7 x + 3

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y = - 2 x^{2} - 12 x - 16

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y = - 2 x^{2} + 16 x - 13

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Solution

The correct options are
A $y = x^{2} + 6 x + 11$
C $y = - 2 x^{2} - 12 x - 16$

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Similar questions

y = 3 x^{2} + 12 x - 12

O A B C

x y -

O

A, B

y = x^{2}

C

y^{2} = 12 x

y^{2} + 6 x - 2 y + 13 = 0

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