CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the work done in stretching a wire by 1mm is 2J, the work necessary for stretching another wire of same material but with double radius of cross-section and half the length by 1mm is:

A
16J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
8J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
14J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 16J
Stretching force, F=Yπr2ΔLL
where the symbols have their usual meanings.
Both the wires are of same material, so Y will be equal, extension in both the wires is same, so ΔL will be equal
Fr2L
FF=(2r)2(L/2)×Lr2=8
or F=8F...(i)
Work done is stretching a wire,
W=12×F×ΔL
For sam extension
WF
WW=FF=8 [Using (i)]
W=8W=8×2J=16J

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hooke's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon