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Question

If θ1 and θ2 are two values lying in [0,2π] for which tanθ=λ, then tanθ12tanθ22 is equal to

A
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B
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C
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1
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Solution

The correct option is B 1
tanθ=λ, we get

2tanθ/21tan2θ/2=λ

λtan2θ2+2tanθ2λ=0

θ1 and θ2 are two values lying in [0,2π] for which tanθ=λ,

So, tanθ12 and tanθ22 are the roots of the above quadratic equation

tanθ12tanθ22=1

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