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Question

If θ(0,2π) and 2cosθ=3cos10sin10, then θ can be

A
20
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B
340
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C
320
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D
40
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Solution

The correct options are
C 320
D 40
2cosθ=3cos10sin10cosθ=32cos1012sin10cosθ=cos30cos10sin30sin10cosθ=cos(30+10)cosθ=cos(40)=cos(320)θ=40=320

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