Question

If three coins are tossed simultaneously then the probability of getting at least two heads is

• A. $\frac{1}{4}$
• B. $\frac{3}{8}$
• C. $\frac{1}{2}$
• D. $\frac{1}{3}$

Answer 1

The correct option is C $\frac{1}{2}$

Possible outcomes of tossing three coins are:
(HHH), (HHT), (HTH), (THH), (TTT), (TTH), (THT),(HTT)
here H and T are denoted for Head and Tail.
Total outcomes = 8
no. of outcomes with at least two heads = 4
$\therefore$ required probability = $\frac{4}{8}=\frac{1}{2}$
$\therefore$ Option C is correct.