Question

If three positive real numbers x, y, z satisfy y - x = z - y and xyz = 4, then what is the minimum possible value of y ?

• A. 2^1/3
• B. 2^2/3
• C. 2^1/4
• D. 2^3/4

Answer 1

The correct option is B

2^2/3

Condition implies x,y,z is in AP and xyz is const. Hence, y is min when x+y+z is min, that will happen when x=y=z= 2${}^{2/3}$