If time for 50 oscillations of the pendulum is 80s using a wrist watch of 1s resolution, then accuracy in measurement of time period is

Open in App

Solution

Suggest Corrections

Similar questions

The period of oscillation of a simple pendulum is $T = 2 π \sqrt{\frac{L}{g}}$ . Measure of $L$ is $20.0 c m$ known to $1 m m$ accuracy and time for $100$ oscillations of the pendulum is found to be $90 s$ using a wrist watch of $1 s$ resolution. The accuracy in the determination of $g$ ?

Q. The period of oscillation of a simple pendulum is T =

2 π \sqrt{\frac{L}{g}}

. Measured value of L is 10 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 50 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g?

The period of oscillation of a simple pendulum is $T = 2 π \sqrt{\frac{L}{g}}$ . Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillation of the pendulum is found to be 90 s using wrist watch of 1 s resolution. The accuracy in the determination of g is: