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Question

If ABC is a right angled triangle, right angled at C, then cos(A+B)=

A
0
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B
12
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C
1
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D
32
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Solution

The correct option is D 0
Given that ABC is a right angled triangle, with C=90o
To find out: The value of cos(A+B)
In ABC,
A+B+C=180o[Angle sum property]
A+B+90o=180o
A+B=180o90o
A+B=90o

Now, cos(A+B)=cos90o
We know that, cos90o=0
cos(A+B)=0

Hence, the required value of cos(A+B) for the given triangle is 0.

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