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Question

If $$\triangle ABC$$ is right angled at $$C$$, then the value of $$\cos(A+B)$$ is


A
0
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B
1
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C
12
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D
32
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Solution

The correct option is A $$0$$
Since ABC is a right angled triangle right angled at C
Hence
$$A+B=180^{0}-C=90^{0}$$
Hence
$$cos(A+B)$$
$$=cos(90^{0})$$
$$=0$$

Mathematics

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