Question

# If $$\triangle ABC$$ is right angled at $$C$$, then the value of $$\cos(A+B)$$ is

A
0
B
1
C
12
D
32

Solution

## The correct option is A $$0$$Since ABC is a right angled triangle right angled at CHence$$A+B=180^{0}-C=90^{0}$$Hence$$cos(A+B)$$$$=cos(90^{0})$$$$=0$$Mathematics

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