If $△$ is right angled at B, AB = 3 cm, BC = 4cm and Ac = 5cm, then find the value of cos C

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Solution

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$a = 4 c m, b = 5 c m, c = 3 c m$
$c o s c = \frac{a^{2} + b^{2} - c^{2}}{2 a b} = \frac{16 + 25 - 9}{2 (20)} = \frac{32}{40} = \frac{4}{5}$

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