Question

If two capillary tubes of radii $r_1$ and $r_2$ in the ratio $1:2$ are dipped vertically in water, then the ratio of capillary rises in the respective tubes is

• A. $1:4$
• B. $4:1$
• C. $1:2$
• D. $2:1$
• E. $1:\sqrt{2}$

Answer 1

The correct option is D $2:1$

Height of water,
$h=\frac{2T\cos \theta }{rdg}$
Since, surface tension and density are same.
$\therefore \frac{h_1}{h_2}=\frac{r_2}{r_1}$
$\therefore \frac{h_1}{h_2}=\frac{2}{1}$