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Question

If velocity of a particle is v(t)=(4t+6) m/s, the magnitude of average velocity of the particle in 10 sec is

A
20 m/s
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B
30 m/s
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C
22 m/s
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D
26 m/s
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Solution

The correct option is D 26 m/s
Given, v(t)=(4t+6)
As we know that,
Displacement s=100(4t+6)dt
s=[2t2+6t]100
s=(2×102+6×10)0=260 m
time taken by the particle is t=10 sec
Hence, average velocity of the particle is given by
26010=26 m/s

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