Question

# If velocity v, acceleration A and force B are chosen as fundamental quantities, then the dimensional formula of angular momentum  in terms of v, A  and F would be

A
B
C
D

Solution

## The correct option is B L ∝vx AyFz⇒ L = kvxAyFz Putting the dimenstions in the above relation [ML2T−1]=k[LT−1]x[LT−2]y[MLT−2]z ⇒[ML2T−1]=k[MzLx+y+z T−x−2y−2z] Comparing the pwers of M,L andT z=1 ...(i) x+y+z =2...(ii) -x-2y-2z =-1 ...(iii) On solving (i),(ii), and (iii) x=3, y=-2 ,z=1  So dimension of L in terms of v,A and f [L] = [Fv3A−2]

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