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Question

If we have a pure Na2CO3 sample that contains a total of 7.8286×1024 electrons, then find the number of moles of Na2CO3 present in the sample.

A
0.5 moles
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B
0.3 moles
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C
0.7 moles
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D
0.25 moles
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Solution

The correct option is D 0.25 moles
Total number of electrons present in one molecule of Na2CO3=(11×2)+6+(3×8)=52.
So, 52×6.022×1024 electrons are present in 1 mole of Na2CO3
Therefore, 7.8286×1024 electrons will be present in
=7.8286 × 102452 × 6.022 × 1023 moles of Na2CO3
= 0.25 moles of Na2CO3

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