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Question

If x>0, x=2 and y=x+x+x+, then the value of 2y1 is

A
2+42
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B
2+43
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C
1+43
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D
1+42
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Solution

The correct option is D 1+42
y=x+x+x+....=x+y

y2y=x

Given x=2

Therefore we get y2y2=0

We have a formula for solving quadratic equation ax2+bx+c=0 is

x=b±b24ac2a


y=1+1+422

2y1=1+42

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