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Question

If x24x+5siny=0,y[0,2π), then

A
x=1,y=0
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B
x=1,y=π2
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C
x=2,y=0
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D
x=2,y=π2
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Solution

The correct option is D x=2,y=π2
(x2)2+1=siny
Since, 1>siny>1, the only possible value of x is 2.
siny=1
y=π2 at x=2
Hence, option 'D' is correct.

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