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Question

If x + 2 is a factor of x2 + ax + 2b and a + b = 4, then

(a) a= 1, b = 3
(b) a = 3, b = 1
(c) a = −1, b = 5
(d) a = 5, b = −1

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Solution

Given that is a factor of and a + b=4

By solving and a + b = 4 by elimination method we get

Multiply by we get,

. So

By substituting b = 1 in a + b = 4 we get

Then a = 3, b = 1

Hence, the correct choice is


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