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Question

If x2+y2=14 and xy=3, find the value of 2(x+y)25(xy)2.


A

0

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B

106

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C

14

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D

52

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Solution

The correct option is A

0


2(x+y)25(xy)2

=2(x2+y2+2xy)5(x22xy+y2)
=2x2+2y2+4xy5x2+10xy5y2
=3x23y2+14xy
=3(x2+y2)+14xy
=(3×14)+(14×3)
=42+42
=0


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