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Question

If x2+y2=14 and xy=3, find the value of 2(x+y)25(xy)2.


  1. 106

  2. 14

  3. 0

  4. 52


Solution

The correct option is C

0


2(x2+y2+2xy)5(x22xy+y2)
= 2x2+2y2+4xy5x2+10xy5y2
= 3x23y2+14xy
= 3(x2+y2)+14xy
= (3×14)+(14×3)
= 42+42
= 0

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