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Question

If x2+y2=t1t and x4+y4=t2+1t2, then x3ydydx equals

A
0
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B
1
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C
1
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D
None of these
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Solution

The correct option is B 1
x2+y2=t1t
Squaring on both sides
x4+y4+2x2y2=t2+1t22
x4+y4=t2+1t2
t2+1t2+2x2y2=t2+1t22
2x2y2=2
x2y2=1
y2=1x2
y=1x1=ix
x3.ydydx;dydx=1x2i
x3.ix=ix2
=i2x3×x3=i2=(1)
=1

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