Given: [x]=2,[y]=−5
Let Z=[x+y+1].
As we know [x+y+1]=[x+y]+1
Now, using the inequality:
[x]+[y]≤[x+y]<[x]+[y]+1
Add 1 one each sides, we get
⇒[x]+[y]+1≤[x+y]+1<[x]+[y]+2
⇒[x]+[y]+1≤[x+y+1]<[x]+[y]+2
⇒[x]+[y]+1≤Z<[x]+[y]+2
⇒2−5+1≤Z<2−5+2
⇒−2≤Z<−1
⇒[x+y+1]∈[−2,−1]
But since [x+y+1] is always an interger
∴[x+y+1]={−2,−1}
Hence the correct answer is Option A.