If x=2t1+t2,y=1-t21+t2, then dydx equals:
2tt2+1
2tt2-1
2t1-t2
None of these
Explanation for the correct option:
Step 1: Find dydt
y=1-t21+t2⇒y=2-1+t21+t2⇒y=21+t2-1⇒dydt=-21+t22×2t⇒dydt=-4t1+t22
Step 2: Find dxdt
x=2t1+t2⇒dxdt=1+t22-2t2t1+t22⇒dxdt=1+t22-2t2t1+t22⇒dxdt=21-t21+t22
Step 3: Find dydx
dydx=-4t1+t2221-t21+t22=-2t1-t2=2tt2-1
Hence, option B is correct.