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Question

If x=3+31/3+32/3 then x39x2+18x12=

A
2
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B
3
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C
0
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D
5
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Solution

The correct option is C 0
x=3+313+323
x3=313+323 ......(1)
(x3)3=(313+323)3
x39x(x3)27=3+32+3×313×323(313+323)
x39x2+27x27=3+9+31+13+23(x3) from (1)
x39x2+27x27=12+9x27
x39x2+18x12=0

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