If x-3 2-1- y-tan 2-2 then x-3 y is equal to

The correct option is B 8 x = 3 sec2θ 1, y = tan2θ 2 x 3y = 3 sec2θ 1 3tan2θ + 6 = 3(1) + 5 = 8 (Since, sec2 θ tan2θ = 1) ...

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Special Integrals - 3

If x=3 2θ-1, ...

Question

If x = 3 sec²θ - 1, y = tan²θ - 2 then x - 3y is equal to

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y = log (\frac{\sqrt{(x + 1)} - 1}{\sqrt{(x + 1)} + 1}) + \frac{\sqrt{x}}{\sqrt{(x + 1)}}

x = {tan}^{2} θ

y

3 ({sec}^{2} θ + {tan}^{2} θ) = 5

2^{x} = 3^{y} = 6^{- z}

(\frac{1}{x} + \frac{1}{y} + \frac{1}{z})

x^{2} + y^{2} = 1

p = (3 x - 4 x^{3})^{2} + (3 y - 4 y^{3})^{2}

P

\frac{y}{x}

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