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Question

If  x=4+15,Find the value of (x2+1x2)


A
58
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B
60
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C
62
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D
32
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Solution

The correct option is C 62
(x2+1x2)=(x+1x)22=(4+15+14+15)22=((4+15)+(415)(4+15)×(415))22=(4+15+415)22=822=62

All India Test Series

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