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Question


If x= cost and y=sin4t then (1x2)y2xy1=

A
4y
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B
4y
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C
16y
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D
16y
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Solution

The correct option is D 16y

dydx=dydtdxdt=4cos4tsint
ddt(dydx)dtdx=d2ydx2

ddt(4cos4tsint)1sint=d2ydx2

+4(4sin4tsintcos4tcost)(sin2t)1sint=y2

4(4sin4tcos4tsintcost)=sin2ty2
16sin4t+costy1=sin2ty2
16y=(1x2)y2xy1


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