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Question

If xϵR and m=x2(x42x2+4), then m lies in the interval

A
[0,14]
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B
[0,13]
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C
[0,12]
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D
[0,15]
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Solution

The correct option is C [0,12]
m=x2(x21)2+3=+ive i.e.0
Again m=1x2+4x22=1(x2x)2+212
mϵ[0,12]

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