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Question

If xϵR and m=x2(x42x2+4), then m lies in the interval
  1. [0,13]
  2. [0,12]
  3. [0,15]
  4. [0,14]


Solution

The correct option is B [0,12]
m=x2(x21)2+3=+ive i.e.0
Again m=1x2+4x22=1(x2x)2+212
mϵ[0,12]

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