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Question

If x=1(23), then find the value of (x32x27x+5).


A

4

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B

8

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C

3

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D

14

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Solution

The correct option is C

3


x=1(23)×(2+3)(2+3)=(2+3)43=(2+3)(x2)=3(x2)2=3x24x+4=3x24x+1=0x32x27x+5=x(x24x+1)+2(x24x+1)+3=x×0+2×0+3=3


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