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Question

If x+y=12 and xy=14, find the value of x2+y2.

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Solution

We have,
(x+y)2=x2+y2+2xy

Putting the values of x+y and xy, we obtain

144=x2+y2+2×14

144=x2+y2+2814428=x2+y2

x2+y2=116

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