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Question

If x+y=12 and xy=32, find the value of x2+y2.



Correct Answer
A

80

Your Answer
B

90

Your Answer
C

100

Your Answer
D

110


Solution

The correct option is A

80


(x+y)2=x2+y2+2xy

144=x2+y2+2×32          [Substituting x + y = 12 and xy = 32]

14464=x2+y2

x2+y2=80

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