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Question

If x,y and z are in AP, then x, y-1 and z are in?
  1. AP
  2. GP
  3. HP
  4. a or b
  5. none of these


Solution

The correct option is C HP

Option (c)    Take y=2 and  = 1 and (y+z)/(1-yz) = 3

 When y=2. x= -1/3 and z= 1/7,     

 = 1/2 = y-1 .. hence they are in HP    

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