If xy-ex-y- then d y-d x-A- log x-1-log x2B- -log x-1-log x2C- log y-1-log y2D- -log y-1-log y2

The correct option is A y=x/1+logx⇒dy/dx=log x/(1+logx)^2 ...

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Implicit Differentiation

If xy=ex-y, t...

Question

If $x^{y} = e^{x - y}, t h e n \frac{d y}{d x} =$

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Similar questions

If $x^{y} = \frac{e^{x}}{e^{y}},$ then $\frac{d y}{d x} =$

\frac{1}{{log}_{x} x y} + \frac{1}{{log}_{y} x y} = 1

{log}_{y} x + {log}_{x} y = 1, x^{2} + y = 12

y^{x} = e^{y - x}

\frac{d y}{d x} = \frac{{(1 + log y)}^{2}}{log y}

a (x - y) = a x - a y

a^{x - y} = a^{x} - a^{y}

log (x - y) = log x - log y

log x / log y = log x - log y

a (x y) = a x \cdot a y

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