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Equation of a Plane : Intercept Form

If x, y, z>=,...

Question

If x, y, z > =, then find the value of xy + yz + zx.

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Solution

You can't simply find xy + yz + zx by knowing just x, y, z range.
You have to be given information about x+y+z and x² + y² + z² for finding xy + yz + zx
If they are given then you can use the formula
(x + y + z)² = x² + y² + z² +2(xy + yz +zx)

However you can get the range of xy + yz + zx if the range of x, y, z are given.

So, as of now this question is wrong and doesn't have a solution.

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Similar questions

(x + y + z) = 9

(x y + y z + z x) = 9

, then find the value of

(x^{2} + y^{2} + z^{2})

.

a^{x} = b^{y} = c^{z}

a b c = 1

, then find the value of

x y + y z + z x

.

x^{y} = z, y^{z} = x

z^{x} = y

, then Find xyz

\frac{x (y + z - x)}{log x} = \frac{y (z + x - y)}{log y} = \frac{z (x + y - z)}{log z}

x^{y} y^{x} + z^{y} y^{z} - 2 x^{z} z^{x}

x^{2} + y^{2} + z^{2} - x y - y z - z x = 0

then the value of

\frac{x + y}{z}

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