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Question

If x²+4y²=4xy,find x:y


Solution

x^2 + 4y^2 - 4xy = 0 
=> x^2 - 2 * x * 2y + (2y)^2 = 0 
=> (x-2y)^2 = 0 
=> x = 2y 
=> x/y = 2 

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