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Question

If y=2ax and dydx=log256 at x=1, then the value of a is?

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is A 0
y=2ax
logy2=ax
logy=(log2)ax
1ydydx=alog2
12a×log256=alog212a×8log2=alog2
8=a×2a
a=2.

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