If |y−3|=|y+1| then the value of y is
1
2
3
4
|y−3|=|y+1| squaring both sides
(y−3)2=(y+1)2
⇒y2−6y+9=y2+2y+1
⇒−6y−2y=1−9
⇒−8y=−8
⇒y=1