If y-cos-1cos x- then dydx at x-5-4 is

The correct option is A ±1 ddx (cos^ 1(cosx)) ⇒ 1√(1 cos^2x).( sinx) ⇒ 1√(sin^2)x sinx ⇒sinx√(sin^2x) ⇒ (± 1) #160; ...

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Integration of Piecewise Continuous Functions

If y=cos-1c...

Question

If $y = {cos}^{- 1} (cos x)$ , then $\frac{d y}{d x}$ at $x = \frac{5 π}{4}$ is

\pm 1

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\frac{1}{\sqrt{2}}

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\frac{5 π}{4}

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Solution

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Similar questions

y = {cos}^{- 1} cos x,

\frac{d y}{d x}

x = \frac{5 π}{4}

y (x) = {cot}^{- 1} (\frac{\sqrt{1 + sin x} + \sqrt{1 - sin x}}{\sqrt{1 + sin x} - \sqrt{1 - sin x}}), x \in (\frac{π}{2}, π),

\frac{d y}{d x}

x = \frac{5 π}{6}

y = \sqrt{5 - x^{2}}

y = | x - 1 |

y (α) = \sqrt{2 (\frac{tan α + cot α}{1 + {tan}^{2} α}) + \frac{1}{{sin}^{2} α}}

α \in (\frac{3 π}{4}, π)

\frac{d y}{d α}

α = \frac{5 π}{6}

y (α) = \sqrt{2 (\frac{tan α + cot α}{1 + {tan}^{2} α}) + \frac{1}{{sin}^{2} α}}

α \in (\frac{3 π}{4}, π)

\frac{d y}{d α}

α = \frac{5 π}{6}

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