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Question

If y=cosx3, then find dydx at x=0
  1. 0
  2. 1
  3. 3
  4. 3


Solution

The correct option is A 0
We have, y=cos x3
Let u=x3,
Differentiating u w.r.t x, we get
dudx=3x2
Also, y=cosu
Differentiating w.r.t u,
dydu=sinu
As we know by chain rule,
dydx=dydududx
dydx=sinu3x2
dydx=(sinx3)3x2
dydxx=0=(sin0)3×0=0
So, option A is correct.

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