y=1x^3 y=x^ 3 Differentiating w.r.t x #160; ddx y=ddxx^ 3 dydx= 3x^ 4 dydx= 3x^4 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration as Antiderivative

If y= 1 x3 ...

Question

If $y = \frac{1}{x^{3}}$ find $\frac{d y}{d x}$

Open in App

Solution

$y = \frac{1}{x^{3}} y = x^{- 3}$
Differentiating w.r.t x
$\frac{d}{d x} y = \frac{d}{d x} x^{- 3} \frac{d y}{d x} = - 3 x^{- 4} \frac{d y}{d x} = \frac{- 3}{x^{4}}$

Suggest Corrections

Similar questions

y = 1 + \frac{1}{x} + \frac{1}{x^{2}} + \frac{1}{x^{3}} + \dots

\infty

| x | > 1

\frac{d y}{d x} =

\frac{d y}{d x}

y = x^{3}

y = 3 x^{2}

\frac{d y}{d x} = ?

(y = x^{5})

\frac{d y}{d x}

\frac{d y}{d x} = x^{5} t a n^{- 1} (x^{3})

Join BYJU'S Learning Program